sin^2(2x)-3cos(2x)=3

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Solution for sin^2(2x)-3cos(2x)=3 equation: 


Simplifying
sin2(2x) + -3cos(2x) = 3

Remove parenthesis around (2x)
in2s * 2x + -3cos(2x) = 3

Reorder the terms for easier multiplication:
2in2s * x + -3cos(2x) = 3

Multiply in2s * x
2in2sx + -3cos(2x) = 3

Remove parenthesis around (2x)
2in2sx + -3cos * 2x = 3

Reorder the terms for easier multiplication:
2in2sx + -3 * 2cos * x = 3

Multiply -3 * 2
2in2sx + -6cos * x = 3

Multiply cos * x
2in2sx + -6cosx = 3

Reorder the terms:
-6cosx + 2in2sx = 3

Solving
-6cosx + 2in2sx = 3

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
-6cosx + 2in2sx + -2in2sx = 3 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
-6cosx + 0 = 3 + -2in2sx
-6cosx = 3 + -2in2sx

Divide each side by '-6osx'.
c = -0.5o-1s-1x-1 + 0.3333333333in2o-1

Simplifying
c = -0.5o-1s-1x-1 + 0.3333333333in2o-1

Reorder the terms:
c = 0.3333333333in2o-1 + -0.5o-1s-1x-1

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